What is the solution for (x^2+y^2)dx-xydy=0 ?

The solution for (x^2+y^2)dx-xydy=0 is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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(x^2+y^2)dx-xydy=0

(x^{2} + y^{2}) d x - x y d y = 0

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

(x^{2} + y^{2}) d x - x y d y = 0

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

\int \frac{6}{x} d x

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What is the solution for (x^2+y^2)dx-xydy=0 ?
The solution for (x^2+y^2)dx-xydy=0 is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}