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Popular >

3y^{''}+48y=0

Solution

3 y^{^{''}} + 48 y = 0

Solution

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Solution steps

3 y^{''} (t) + 48 y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Popular Examples

integral of (y^4)/4

\int \frac{y ^{4}}{4} d y

integral of (x-csc(x)cot(x))

\int (x - csc (x) cot (x)) d x

f(x)=x^2*e^{4x}

f (x) = x^{2} \cdot e^{4 x}

integral from 1 to infinity of 1/(x^2-x)

\int_{1}^{\infty} \frac{1}{x ^{2} - x} d x

derivative of 4x^3+4

\frac{d}{d x} (4 x^{3} + 4)

Frequently Asked Questions (FAQ)

What is the solution for 3y^{''}+48y=0 ?
The solution for 3y^{''}+48y=0 is y=c_{1}cos(4t)+c_{2}sin(4t)