What is the derivative of 4x^3+4 ?

The derivative of 4x^3+4 is 12x^2

What is the first derivative of 4x^3+4 ?

The first derivative of 4x^3+4 is 12x^2

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\frac{d}{d x} (4 x^{3} + 4)

12 x^{2}

Solution steps

\frac{d}{d x} (4 x^{3} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (4)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (4) = 0

= 12 x^{2} + 0

Simplify

= 12 x^{2}

x \frac{d y}{d x} = 3 y

\int \frac{d}{1} (\frac{1}{x}) d x

n = 1 \sum \infty \frac{8}{( n ) ( n + 3 )}

\int u^{- 3} (9 - u^{3} + u^{6}) d u

What is the derivative of 4x^3+4 ?
The derivative of 4x^3+4 is 12x^2
What is the first derivative of 4x^3+4 ?
The first derivative of 4x^3+4 is 12x^2