What is the integral of 1 (1/x) ?

The integral of 1 (1/x) is dln|x|+C

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integral of 1 (1/x)

\int \frac{d}{1} (\frac{1}{x}) d x

d ln ∣ x ∣ + C

Solution steps

\int \frac{d}{1} \cdot \frac{1}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= d ln ∣ x ∣

Add a constant to the solution

= d ln ∣ x ∣ + C

n = 1 \sum \infty \frac{8}{( n ) ( n + 3 )}

\int u^{- 3} (9 - u^{3} + u^{6}) d u

x \to 0 lim \frac{( ( x + 64 ) ^{\frac{1}{3}} - 4 )}{x}

\frac{d}{d x} (322560 (2 x + 5))