What is the derivative of x^2+6x ?

The derivative of x^2+6x is 2x+6

What is the first derivative of x^2+6x ?

The first derivative of x^2+6x is 2x+6

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\frac{d}{d x} (x^{2} + 6 x)

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

= 2 x + 6

f (x) = \frac{x ^{\frac{1}{2}}}{x + 9}, at x = 1

x d y - y d x + y^{2} d x = 0

\frac{d}{d x} (4 sinh (2 x))

\frac{\partial}{\partial y} (e^{1 - x y})

x \to 1 - lim (\frac{1}{x + 1})