What is (\partial)/(\partial y)(e^{1-xy}) ?

The answer to (\partial)/(\partial y)(e^{1-xy}) is -e^{1-xy}x

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(\partial)/(\partial y)(e^{1-xy})

\frac{\partial}{\partial y} (e^{1 - x y})

- e^{1 - x y} x

Solution steps

\frac{\partial}{\partial y} (e^{1 - x y})

Treat

x

as a constant

Apply the chain rule:

e^{1 - x y} \frac{\partial}{\partial y} (1 - x y)

= e^{1 - x y} \frac{\partial}{\partial y} (1 - x y)

\frac{\partial}{\partial y} (1 - x y) = - x

= e^{1 - x y} (- x)

Simplify

= - e^{1 - x y} x

x \to 1 - lim (\frac{1}{x + 1})

\int_{- π}^{π} t sin (n t) d t

x \to - 1 lim (x^{2} - 6 x - 7)

\frac{d}{d x} (e^{x} + x)

(x - y) d x - (x + y) d y = 0

What is (\partial)/(\partial y)(e^{1-xy}) ?
The answer to (\partial)/(\partial y)(e^{1-xy}) is -e^{1-xy}x