What is (\partial)/(\partial x)(y/x ln(x)) ?

The answer to (\partial)/(\partial x)(y/x ln(x)) is (y(-ln(x)+1))/(x^2)

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(\partial)/(\partial x)(y/x ln(x))

\frac{\partial}{\partial x} (\frac{y}{x} ln (x))

\frac{y ( - ln ( x ) + 1 )}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{y}{x} ln (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (\frac{1}{x} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{x}, g = ln (x)

= y (\frac{\partial}{\partial x} (\frac{1}{x}) ln (x) + \frac{\partial}{\partial x} (ln (x)) \frac{1}{x})

\frac{\partial}{\partial x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= y ((- \frac{1}{x ^{2}}) ln (x) + \frac{1}{x} \cdot \frac{1}{x})

Simplify

y ((- \frac{1}{x ^{2}}) ln (x) + \frac{1}{x} \cdot \frac{1}{x}) : \frac{y ( - ln ( x ) + 1 )}{x ^{2}}

= \frac{y ( - ln ( x ) + 1 )}{x ^{2}}

n = 1 \sum \infty (cos (2.6))^{n}

\int (5 x + 1)^{\frac{1}{2}} d x

y^{^{''}} + 4 y = 3 cos (2 t)

\frac{d}{d n} (n^{n})

n = 0 \sum \infty n! (x - 5)^{n}

What is (\partial)/(\partial x)(y/x ln(x)) ?
The answer to (\partial)/(\partial x)(y/x ln(x)) is (y(-ln(x)+1))/(x^2)