What is the solution for (dr)/(dθ)=(r^2+2rθ)/(θ^2) ?

The solution for (dr)/(dθ)=(r^2+2rθ)/(θ^2) is r(θ)=(θ^2)/(-θ+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dr)/(dθ)=(r^2+2rθ)/(θ^2)

\frac{d r}{d θ} = \frac{r ^{2} + 2 r θ}{θ ^{2}}

r (θ) = \frac{θ ^{2}}{- θ + c _{1}}

Solution steps

\frac{d r}{d θ} = \frac{r ^{2} + 2 r θ}{θ ^{2}}

Solve Bernoulli ODE:

r (θ) = \frac{θ ^{2}}{- θ + c _{1}}

r (θ) = \frac{θ ^{2}}{- θ + c _{1}}

x \to 0 lim (\frac{x}{sin ( 8 x )})

x \to 1 lim (e^{x - 1} + 1)

\frac{\partial}{\partial x} (x ln (z^{7} + x^{4}))

y = x^{2} - 4 x - 3, (3, - 6)

(\frac{1}{x}), (\frac{1}{x ^{2}}), 2

What is the solution for (dr)/(dθ)=(r^2+2rθ)/(θ^2) ?
The solution for (dr)/(dθ)=(r^2+2rθ)/(θ^2) is r(θ)=(θ^2)/(-θ+c_{1)}