What is the derivative of f(x)=arcsin(2x-3) ?

The derivative of f(x)=arcsin(2x-3) is 1/(sqrt(-x^2+3x-2))

What is the first derivative of f(x)=arcsin(2x-3) ?

The first derivative of f(x)=arcsin(2x-3) is 1/(sqrt(-x^2+3x-2))

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derivative of

f (x) = arcsin (2 x - 3)

\frac{1}{- x ^{2} + 3 x - 2}

Solution steps

\frac{d}{d x} (arcsin (2 x - 3))

Apply the chain rule:

\frac{1}{1 - ( 2 x - 3 ) ^{2}} \frac{d}{d x} (2 x - 3)

= \frac{1}{1 - ( 2 x - 3 ) ^{2}} \frac{d}{d x} (2 x - 3)

\frac{d}{d x} (2 x - 3) = 2

= \frac{1}{1 - ( 2 x - 3 ) ^{2}} \cdot 2

Simplify

\frac{1}{1 - ( 2 x - 3 ) ^{2}} \cdot 2 : \frac{1}{- x ^{2} + 3 x - 2}

= \frac{1}{- x ^{2} + 3 x - 2}

\frac{d}{d x} (6 tan^{2} (3 x))

\int \frac{6 x ^{2} + x + 7}{( x + 1 ) ( x ^{2} + 1 )} d x

\frac{d y}{d x} = \frac{y}{x} + 4 x + 9

\frac{d y}{d x} + 3 y = 2 x e^{- 3 x}

n = 0 \sum \infty \frac{1}{1.0 2 ^{n}}

What is the derivative of f(x)=arcsin(2x-3) ?
The derivative of f(x)=arcsin(2x-3) is 1/(sqrt(-x^2+3x-2))
What is the first derivative of f(x)=arcsin(2x-3) ?
The first derivative of f(x)=arcsin(2x-3) is 1/(sqrt(-x^2+3x-2))