What is the derivative of arccos(|x+1|) ?

The derivative of arccos(|x+1|) is -(x+1)/(|x+1|sqrt(-x^2-2x))

What is the first derivative of arccos(|x+1|) ?

The first derivative of arccos(|x+1|) is -(x+1)/(|x+1|sqrt(-x^2-2x))

Popular >

derivative of

arccos (∣ x + 1 ∣)

- \frac{x + 1}{∣ x + 1 ∣ - x ^{2} - 2 x}

Solution steps

\frac{d}{d x} (arccos (∣ x + 1 ∣))

Apply the chain rule:

- \frac{1}{1 - ∣ x + 1 ∣ ^{2}} \frac{d}{d x} (∣ x + 1 ∣)

= - \frac{1}{1 - ∣ x + 1 ∣ ^{2}} \frac{d}{d x} (∣ x + 1 ∣)

\frac{d}{d x} (∣ x + 1 ∣) = \frac{x + 1}{∣ x + 1 ∣}

= - \frac{1}{1 - ∣ x + 1 ∣ ^{2}} \cdot \frac{x + 1}{∣ x + 1 ∣}

Simplify

- \frac{1}{1 - ∣ x + 1 ∣ ^{2}} \cdot \frac{x + 1}{∣ x + 1 ∣} : - \frac{x + 1}{∣ x + 1 ∣ - x ^{2} - 2 x}

= - \frac{x + 1}{∣ x + 1 ∣ - x ^{2} - 2 x}

f (x) = 2 x^{2} - 5 x + 3, at a = 2

\frac{\partial}{\partial x} (ln (2 x^{2} + x y))

\int \frac{1}{x 100 x ^{2} - 100} d x

f (x) = x^{9} e^{x}

y^{\frac{1}{2}} y^{^{'}} + y^{\frac{3}{2}} = 1

What is the derivative of arccos(|x+1|) ?
The derivative of arccos(|x+1|) is -(x+1)/(|x+1|sqrt(-x^2-2x))
What is the first derivative of arccos(|x+1|) ?
The first derivative of arccos(|x+1|) is -(x+1)/(|x+1|sqrt(-x^2-2x))