What is the integral of 3xcos(y) ?

The integral of 3xcos(y) is 3xsin(y)+C

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integral of 3xcos(y)

\int 3 x cos (y) d y

3 x sin (y) + C

Solution steps

\int 3 x cos (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 x \cdot \int cos (y) d y

Use the common integral:

\int cos (y) d y = sin (y)

= 3 x sin (y)

Add a constant to the solution

= 3 x sin (y) + C

t^{2} y^{^{''}} - 3 t y^{^{'}} + 3 y = 0

\frac{\partial}{\partial x} (81 - 9 x^{2} - y^{2})

y^{2} = 5 x^{4} - x^{2}, (- 1, 2)

\int \frac{1}{y ^{2} ( y ^{2} + 1 )} d y

M^{2} (\frac{C}{2} - \frac{M}{3})