What is the integral of (\sqrt[8]{x}) ?

The integral of (\sqrt[8]{x}) is 8/9 x^{9/8}+C

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integral of (\sqrt[8]{x})

\int (8 x) d x

\frac{8}{9} x^{\frac{9}{8}} + C

Solution steps

\int 8 x d x

Apply the Power Rule

: \frac{8}{9} x^{\frac{9}{8}}

= \frac{8}{9} x^{\frac{9}{8}}

Add a constant to the solution

= \frac{8}{9} x^{\frac{9}{8}} + C

\int x^{2} in (2 x) d x

x^{2} y^{^{''}} + x y^{^{'}} - 9 y = 0

\int_{1}^{t} \frac{13}{x ^{3}} d x

\frac{d}{d x} (e^{x} sin (2 x) + 2 e^{x} cos (2 x))

\frac{x}{x + 17}

What is the integral of (\sqrt[8]{x}) ?
The integral of (\sqrt[8]{x}) is 8/9 x^{9/8}+C