What is the solution for x^2y^{''}+xy^'-9y=0 ?

The solution for x^2y^{''}+xy^'-9y=0 is y=c_{1}x^3+(c_{2})/(x^3)

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x^2y^{''}+xy^'-9y=0

x^{2} y^{^{''}} + x y^{^{'}} - 9 y = 0

y = c_{1} x^{3} + \frac{c _{2}}{x ^{3}}

Solution steps

x^{2} y^{''} (x) + x y^{'} (x) - 9 y = 0

Solve linear ODE:

y = c_{1} x^{3} + \frac{c _{2}}{x ^{3}}

y = c_{1} x^{3} + \frac{c _{2}}{x ^{3}}

\int_{1}^{t} \frac{13}{x ^{3}} d x

\frac{d}{d x} (e^{x} sin (2 x) + 2 e^{x} cos (2 x))

\frac{x}{x + 17}

y = 9 - x^{2}, y = 4 x

\int \frac{x}{( 1 + x ^{2} ) ^{3}} d x

What is the solution for x^2y^{''}+xy^'-9y=0 ?
The solution for x^2y^{''}+xy^'-9y=0 is y=c_{1}x^3+(c_{2})/(x^3)