What is area y=9-x^2,y=4x ?

The answer to area y=9-x^2,y=4x is -(50sqrt(13))/3+34sqrt(13)

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area y=9-x^2,y=4x

area

y = 9 - x^{2}, y = 4 x

- \frac{50 13}{3} + 3413

Decimal

62.49622 \dots

Solution steps

Apply the area formula:

\int_{- 2 - 13}^{13 - 2} 9 - x^{2} - 4 x d x

Solve

\int_{- 2 - 13}^{13 - 2} 9 - x^{2} - 4 x d x : - \frac{50 13}{3} + 3413

The area is:

= - \frac{50 13}{3} + 3413

\int \frac{x}{( 1 + x ^{2} ) ^{3}} d x

(2 x + 5)^{2}

\int_{- 1}^{0} x^{\frac{1}{3}} - x^{\frac{2}{3}} d x

\int \frac{2 x}{( x ^{2} + y ^{2} ) ^{2}} d x

\int x^{2} x^{3} + 13 d x

What is area y=9-x^2,y=4x ?
The answer to area y=9-x^2,y=4x is -(50sqrt(13))/3+34sqrt(13)