What is the integral of (2x)/((x^2+y^2)^2) ?

The integral of (2x)/((x^2+y^2)^2) is -1/(y^2+x^2)+C

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integral of (2x)/((x^2+y^2)^2)

\int \frac{2 x}{( x ^{2} + y ^{2} ) ^{2}} d x

- \frac{1}{y ^{2} + x ^{2}} + C

Solution steps

\int \frac{2 x}{( x ^{2} + y ^{2} ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{x}{( y ^{2} + x ^{2} ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{2 u ^{2}} d u

= 2 \cdot \int \frac{1}{2 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= 2 \cdot \frac{1}{2} (- \frac{1}{u})

Substitute back

u = y^{2} + x^{2}

= 2 \cdot \frac{1}{2} (- \frac{1}{y ^{2} + x ^{2}})

Simplify

2 \cdot \frac{1}{2} (- \frac{1}{y ^{2} + x ^{2}}) : - \frac{1}{y ^{2} + x ^{2}}

= - \frac{1}{y ^{2} + x ^{2}}

Add a constant to the solution

= - \frac{1}{y ^{2} + x ^{2}} + C

\int x^{2} x^{3} + 13 d x

2 x^{2} + 10 x + 9

y = ln (7 x)

\frac{d}{d x} (cos (x) - 7 x)

n = 0 \sum \infty - 2^{n}

What is the integral of (2x)/((x^2+y^2)^2) ?
The integral of (2x)/((x^2+y^2)^2) is -1/(y^2+x^2)+C