What is the derivative of Insqrt(3x+4) ?

The derivative of Insqrt(3x+4) is (3nI)/(2sqrt(3x+4))

What is the first derivative of Insqrt(3x+4) ?

The first derivative of Insqrt(3x+4) is (3nI)/(2sqrt(3x+4))

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\frac{d}{d x} (I n 3 x + 4)

\frac{3 n I}{2 3 x + 4}

Solution steps

\frac{d}{d x} (I n 3 x + 4)

Treat

n, I

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= I n \frac{d}{d x} (3 x + 4)

Apply the chain rule:

\frac{1}{2 3 x + 4} \frac{d}{d x} (3 x + 4)

= \frac{1}{2 3 x + 4} \frac{d}{d x} (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

= I n \frac{1}{2 3 x + 4} \cdot 3

Simplify

I n \frac{1}{2 3 x + 4} \cdot 3 : \frac{3 n I}{2 3 x + 4}

= \frac{3 n I}{2 3 x + 4}

\frac{s - 8}{2 s ^{2} + s + 12}

\int \frac{x ^{2} + x + 2}{( x + 1 ) ( x ^{2} + 1 )} d x

\frac{d}{d x} (x - sin (x) cos (x))

\int \frac{1}{2 x ^{3}} - \frac{1}{x ^{4}} d x

\frac{d}{d x} (\frac{sec ( x )}{8 + sec ( x )})

What is the derivative of Insqrt(3x+4) ?
The derivative of Insqrt(3x+4) is (3nI)/(2sqrt(3x+4))
What is the first derivative of Insqrt(3x+4) ?
The first derivative of Insqrt(3x+4) is (3nI)/(2sqrt(3x+4))