What is the derivative of (sec(x)/(8+sec(x))) ?

The derivative of (sec(x)/(8+sec(x))) is (8sec(x)tan(x))/((8+sec(x))^2)

What is the first derivative of (sec(x)/(8+sec(x))) ?

The first derivative of (sec(x)/(8+sec(x))) is (8sec(x)tan(x))/((8+sec(x))^2)

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\frac{d}{d x} (\frac{sec ( x )}{8 + sec ( x )})

\frac{8 sec ( x ) tan ( x )}{( 8 + sec ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{sec ( x )}{8 + sec ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( sec ( x ) ) ( 8 + sec ( x ) ) - \frac{d}{d x} ( 8 + sec ( x ) ) sec ( x )}{( 8 + sec ( x ) ) ^{2}}

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d}{d x} (8 + sec (x)) = sec (x) tan (x)

= \frac{sec ( x ) tan ( x ) ( 8 + sec ( x ) ) - sec ( x ) tan ( x ) sec ( x )}{( 8 + sec ( x ) ) ^{2}}

Simplify

\frac{sec ( x ) tan ( x ) ( 8 + sec ( x ) ) - sec ( x ) tan ( x ) sec ( x )}{( 8 + sec ( x ) ) ^{2}} : \frac{8 sec ( x ) tan ( x )}{( 8 + sec ( x ) ) ^{2}}

= \frac{8 sec ( x ) tan ( x )}{( 8 + sec ( x ) ) ^{2}}

f (x) = - csc (x) cot (x)

sin (x^{0.5})

(x^{2} + 1) (2 x + 5 + \frac{8}{x})

y = \frac{x ^{2} - 4 x}{x + 1}

\int 8 x cos (3 x) d x

What is the derivative of (sec(x)/(8+sec(x))) ?
The derivative of (sec(x)/(8+sec(x))) is (8sec(x)tan(x))/((8+sec(x))^2)
What is the first derivative of (sec(x)/(8+sec(x))) ?
The first derivative of (sec(x)/(8+sec(x))) is (8sec(x)tan(x))/((8+sec(x))^2)