What is the derivative of f(x)=-csc(x)cot(x) ?

The derivative of f(x)=-csc(x)cot(x) is -csc(x)+2csc^3(x)

What is the first derivative of f(x)=-csc(x)cot(x) ?

The first derivative of f(x)=-csc(x)cot(x) is -csc(x)+2csc^3(x)

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derivative of

f (x) = - csc (x) cot (x)

- csc (x) + 2 csc^{3} (x)

Solution steps

\frac{d}{d x} (- csc (x) cot (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (csc (x) cot (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = csc (x), g = cot (x)

= - (\frac{d}{d x} (csc (x)) cot (x) + \frac{d}{d x} (cot (x)) csc (x))

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= - ((- cot (x) csc (x)) cot (x) + (- csc^{2} (x)) csc (x))

Simplify

- ((- cot (x) csc (x)) cot (x) + (- csc^{2} (x)) csc (x)) : - csc (x) + 2 csc^{3} (x)

= - csc (x) + 2 csc^{3} (x)

sin (x^{0.5})

(x^{2} + 1) (2 x + 5 + \frac{8}{x})

y = \frac{x ^{2} - 4 x}{x + 1}

\int 8 x cos (3 x) d x

\frac{d}{d x} (cos (k x))

What is the derivative of f(x)=-csc(x)cot(x) ?
The derivative of f(x)=-csc(x)cot(x) is -csc(x)+2csc^3(x)
What is the first derivative of f(x)=-csc(x)cot(x) ?
The first derivative of f(x)=-csc(x)cot(x) is -csc(x)+2csc^3(x)