What is the solution for x(x+3)dy-y(2x+3)dx=0 ?

The solution for x(x+3)dy-y(2x+3)dx=0 is y=e^{c_{1}}x^2+3e^{c_{1}}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(x+3)dy-y(2x+3)dx=0

x (x + 3) d y - y (2 x + 3) d x = 0

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} x

Solution steps

x (x + 3) d y - y (2 x + 3) d x = 0

Solve separable ODE:

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} x

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} x

(x^{3} + 2)^{^{'}}

\int 2 t - cos (6 t) d t

\int_{0}^{1} \frac{34}{4 y - 1} d y

y^{^{'}} = e^{2 x - 1} y^{2}

x y^{^{'}} - 2 y = x^{3} e^{x}

What is the solution for x(x+3)dy-y(2x+3)dx=0 ?
The solution for x(x+3)dy-y(2x+3)dx=0 is y=e^{c_{1}}x^2+3e^{c_{1}}x