What is the solution for (dy)/(dx)=(y+1)^{(-1)} ?

The solution for (dy)/(dx)=(y+1)^{(-1)} is y=-1+sqrt(2(x+c_{1))+1},y=-sqrt(2(x+c_{1))+1}-1

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(dy)/(dx)=(y+1)^{(-1)}

\frac{d y}{d x} = (y + 1)^{(- 1)}

y = - 1 + 2 (x + c_{1}) + 1, y = - 2 (x + c_{1}) + 1 - 1

Solution steps

\frac{d y}{d x} = (y + 1)^{(- 1)}

Solve separable ODE:

y = - 1 + 2 (x + c_{1}) + 1, y = - 2 (x + c_{1}) + 1 - 1

y = - 1 + 2 (x + c_{1}) + 1, y = - 2 (x + c_{1}) + 1 - 1

x^{^{''}} + 25 x = 0

\frac{d}{d x} (e^{x} cos (x))

\frac{d}{d x} (ln (e^{x} + 7 x + 1))

\frac{\partial}{\partial r} (r \cdot cos (t))

\int_{2}^{1} 12 x^{- 5} d x

What is the solution for (dy)/(dx)=(y+1)^{(-1)} ?
The solution for (dy)/(dx)=(y+1)^{(-1)} is y=-1+sqrt(2(x+c_{1))+1},y=-sqrt(2(x+c_{1))+1}-1