What is the tangent of f(x)=6x^2+8x ?

The tangent of f(x)=6x^2+8x is y=(12a_{0}+8)x-6a_{0}^2

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tangent of f(x)=6x^2+8x

tangent of

f (x) = 6 x^{2} + 8 x

y = (12 a_{0} + 8) x - 6 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2} + 8 a_{0})

Find the slope of

f (x) = 6 x^{2} + 8 x : \frac{df ( x )}{d x} = 12 x + 8

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12 a_{0} + 8

Find the line with slope m=

12 a_{0} + 8

and passing through

(a_{0}, 6 a_{0}^{2} + 8 a_{0}) : y = (12 a_{0} + 8) x - 6 a_{0}^{2}

y = (12 a_{0} + 8) x - 6 a_{0}^{2}

\frac{x}{2 - tan ( x )}

\frac{d}{d x} (sin (2 x) cos (x))

\frac{\partial}{\partial x} (tan (x))

\frac{d ^{4}}{d x ^{4}} (3 e^{x^{2}})

4 y^{^{''}} - 4 y^{^{'}} + y = 0

What is the tangent of f(x)=6x^2+8x ?
The tangent of f(x)=6x^2+8x is y=(12a_{0}+8)x-6a_{0}^2