What is the integral of (2y)/1 ^2 ?

The integral of (2y)/1 ^2 is d^2yx^2+C

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integral of (2y)/1 ^2

\int \frac{d ^{2} y}{1} d x^{2}

d^{2} y x^{2} + C

Solution steps

\int \frac{d ^{2} y}{1} d x^{2}

Integral of a constant:

\int a d x = a x

= \frac{d ^{2} y}{1} x^{2}

Simplify

= d^{2} y x^{2}

Add a constant to the solution

= d^{2} y x^{2} + C

\int (sin^{2} (x) + cos^{2} (x) - 1) d x

\int - \frac{6 x}{5} d x

y = (x^{3} - 25 x)^{14}

f (x) = (8 - x)^{6}

x \to 0 + lim (\frac{- 1}{x})