What is (\partial)/(\partial x)(-3xy^2) ?

The answer to (\partial)/(\partial x)(-3xy^2) is -3y^2

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(\partial)/(\partial x)(-3xy^2)

\frac{\partial}{\partial x} (- 3 x y^{2})

- 3 y^{2}

Solution steps

\frac{\partial}{\partial x} (- 3 x y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 y^{2} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - 3 y^{2} \cdot 1

Simplify

= - 3 y^{2}

x \to 0 - lim (\frac{2}{x} - \frac{2}{∣ x ∣})

\frac{d}{d x} (6 x^{5} - 20 x^{4} + 20 x^{3} - 10 x + 4)

\int_{0}^{1} π (2 - \frac{1}{2} x)^{2} d x

\frac{\partial}{\partial t} (4 cos (t))

x \to 0 lim (\frac{1}{x} - \frac{1}{x})

What is (\partial)/(\partial x)(-3xy^2) ?
The answer to (\partial)/(\partial x)(-3xy^2) is -3y^2