What is (\partial)/(\partial t)(4cos(t)) ?

The answer to (\partial)/(\partial t)(4cos(t)) is -4sin(t)

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(\partial)/(\partial t)(4cos(t))

\frac{\partial}{\partial t} (4 cos (t))

- 4 sin (t)

Solution steps

\frac{\partial}{\partial t} (4 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial t} (cos (t))

Apply the common derivative:

\frac{\partial}{\partial t} (cos (t)) = - sin (t)

= 4 (- sin (t))

Simplify

= - 4 sin (t)

x \to 0 lim (\frac{1}{x} - \frac{1}{x})

y = \frac{5}{x ^{2} + 1}, (2, 1)

\int 7 x cos (8 x) d x

\int x cos (4 x) d x

x^{2} + 3 x + 9

What is (\partial)/(\partial t)(4cos(t)) ?
The answer to (\partial)/(\partial t)(4cos(t)) is -4sin(t)