What is (\partial)/(\partial x)(3x^2-y) ?

The answer to (\partial)/(\partial x)(3x^2-y) is 6x

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(\partial)/(\partial x)(3x^2-y)

\frac{\partial}{\partial x} (3 x^{2} - y)

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y) = 0

= 6 x - 0

Simplify

= 6 x

\int \frac{4}{x ^{3} + 4 x} d x

(x^{2} + 3) cos (- 3 x)

x \to 2 π + lim (x csc (x))

\int_{2}^{3} \frac{15}{3 - x} d x

What is (\partial)/(\partial x)(3x^2-y) ?
The answer to (\partial)/(\partial x)(3x^2-y) is 6x