What is the limit as x approaches 2pi+of xcsc(x) ?

The limit as x approaches 2pi+of xcsc(x) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2pi+of xcsc(x)

x \to 2 π + lim (x csc (x))

\infty

Solution steps

x \to 2 π + lim (x csc (x))

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 2 π + lim (x) \cdot x \to 2 π + lim (csc (x))

x \to 2 π + lim (x) = 2 π

x \to 2 π + lim (csc (x)) = \infty

= 2 π \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

\int_{2}^{3} \frac{15}{3 - x} d x

- x^{2} + y = 1, [2, - 2]

\int (r^{2} + r + 1) e^{r} d r

x \to 1 + lim (\frac{x ^{2} - 8 x + 15}{x - 1})

What is the limit as x approaches 2pi+of xcsc(x) ?
The limit as x approaches 2pi+of xcsc(x) is infinity