What is the solution for 2xydx+(x^2+1)dy=3xdx ?

The solution for 2xydx+(x^2+1)dy=3xdx is y=(c_{1})/(2(x^2+1))+3/2

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2xydx+(x^2+1)dy=3xdx

2 x y d x + (x^{2} + 1) d y = 3 x d x

y = \frac{c _{1}}{2 ( x ^{2} + 1 )} + \frac{3}{2}

Solution steps

2 x y d x + (x^{2} + 1) d y = 3 x d x

Solve separable ODE:

y = \frac{c _{1}}{2 ( x ^{2} + 1 )} + \frac{3}{2}

y = \frac{c _{1}}{2 ( x ^{2} + 1 )} + \frac{3}{2}

\frac{\partial}{\partial r} (e^{r} cos (θ))

\int \frac{x ^{2} - 2 x + 1}{x ^{2} - 2 x + 10} d x

\int (2 x^{2} + 5) (x^{2} - 3 x) d x

\int \frac{1}{y ^{3}} d y

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}})

What is the solution for 2xydx+(x^2+1)dy=3xdx ?
The solution for 2xydx+(x^2+1)dy=3xdx is y=(c_{1})/(2(x^2+1))+3/2