What is the derivative of 5e^x+8/(\sqrt[3]{x}) ?

The derivative of 5e^x+8/(\sqrt[3]{x}) is 5e^x-8/(3x^{4/3)}

What is the first derivative of 5e^x+8/(\sqrt[3]{x}) ?

The first derivative of 5e^x+8/(\sqrt[3]{x}) is 5e^x-8/(3x^{4/3)}

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5 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= 5 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

\int_{- 3}^{- 1} \frac{1}{x} d x

x - \frac{1}{x}

\frac{d}{d x} (6 x ln (x))

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\frac{d}{d x} (\frac{6 ( x - 3 ) ^{2}}{3 x ^{2} - 9 x - 12})

What is the derivative of 5e^x+8/(\sqrt[3]{x}) ?
The derivative of 5e^x+8/(\sqrt[3]{x}) is 5e^x-8/(3x^{4/3)}
What is the first derivative of 5e^x+8/(\sqrt[3]{x}) ?
The first derivative of 5e^x+8/(\sqrt[3]{x}) is 5e^x-8/(3x^{4/3)}