Solution
Solution
Solution steps
Take the constant out:
Complete the square
Apply u-substitution
Apply Trigonometric Substitution
Use the common integral:
Substitute back
Simplify
Add a constant to the solution
Graph
Popular Examples
area-x^2+16,-1/4 x-1,x-6.6area derivative of sqrt(7x+5)y'=y^3-4ylimit as x approaches 0+of (3x)^{5x}integral of 1/(1-y^2)
Frequently Asked Questions (FAQ)
What is the integral of 3/(sqrt(x^2-6x-7)) ?
The integral of 3/(sqrt(x^2-6x-7)) is 3ln(1/4 |sqrt(x^2-6x-7)+x-3|)+C