What is the solution for 5/2 y^4y^'=(sqrt(y^5+4))/(x^3) ?

The solution for 5/2 y^4y^'=(sqrt(y^5+4))/(x^3) is y=\sqrt[5]{1/(4x^4)-(c_{1})/(x^2)+c_{1}^2-4}

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5/2 y^4y^'=(sqrt(y^5+4))/(x^3)

\frac{5}{2} y^{4} y^{^{'}} = \frac{y ^{5} + 4}{x ^{3}}

Solution steps

\frac{5}{2} y^{4} y^{'} (x) = \frac{y ^{5} + 4}{x ^{3}}

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What is the solution for 5/2 y^4y^'=(sqrt(y^5+4))/(x^3) ?
The solution for 5/2 y^4y^'=(sqrt(y^5+4))/(x^3) is y=\sqrt[5]{1/(4x^4)-(c_{1})/(x^2)+c_{1}^2-4}