What is the solution for 121y^{''}+198y^'+65y=0 ?

The solution for 121y^{''}+198y^'+65y=0 is y=c_{1}e^{-(5t)/(11)}+c_{2}e^{-(13t)/(11)}

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121y^{''}+198y^'+65y=0

121 y^{^{''}} + 198 y^{^{'}} + 65 y = 0

y = c_{1} e^{- \frac{5 t}{11}} + c_{2} e^{- \frac{13 t}{11}}

Solution steps

121 y^{''} (t) + 198 y^{'} (t) + 65 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{5 t}{11}} + c_{2} e^{- \frac{13 t}{11}}

y = c_{1} e^{- \frac{5 t}{11}} + c_{2} e^{- \frac{13 t}{11}}

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(1 + ln (x) + \frac{y}{x}) d x = (1 - ln (x)) d y

\frac{d}{d x} (7 - 4 e^{- x})

(- \frac{q ^{4}}{4} + \frac{2 q ^{3}}{3} + \frac{11 q ^{2}}{2} - 12 q)^{^{'}}

3 e^{6 x} \frac{d y}{d x} = - 36 \frac{x}{y ^{2}}

What is the solution for 121y^{''}+198y^'+65y=0 ?
The solution for 121y^{''}+198y^'+65y=0 is y=c_{1}e^{-(5t)/(11)}+c_{2}e^{-(13t)/(11)}