What is the derivative of 7-4e^{-x} ?

The derivative of 7-4e^{-x} is 4e^{-x}

What is the first derivative of 7-4e^{-x} ?

The first derivative of 7-4e^{-x} is 4e^{-x}

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\frac{d}{d x} (7 - 4 e^{- x})

4 e^{- x}

Solution steps

\frac{d}{d x} (7 - 4 e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7) - \frac{d}{d x} (4 e^{- x})

\frac{d}{d x} (7) = 0

\frac{d}{d x} (4 e^{- x}) = - 4 e^{- x}

= 0 - (- 4 e^{- x})

Simplify

= 4 e^{- x}

(- \frac{q ^{4}}{4} + \frac{2 q ^{3}}{3} + \frac{11 q ^{2}}{2} - 12 q)^{^{'}}

3 e^{6 x} \frac{d y}{d x} = - 36 \frac{x}{y ^{2}}

\int_{\frac{1}{5}}^{7} 6 x ln (5 x) d x

f (x) = (x^{2} - 9)^{2}

\frac{d y}{d x} = \frac{3 y ^{2} cot ( x ) + sin ( x ) cos ( x )}{2 y}

What is the derivative of 7-4e^{-x} ?
The derivative of 7-4e^{-x} is 4e^{-x}
What is the first derivative of 7-4e^{-x} ?
The first derivative of 7-4e^{-x} is 4e^{-x}