What is the derivative of y=ln(2-9x) ?

The derivative of y=ln(2-9x) is -9/(2-9x)

What is the first derivative of y=ln(2-9x) ?

The first derivative of y=ln(2-9x) is -9/(2-9x)

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derivative of

y = ln (2 - 9 x)

- \frac{9}{2 - 9 x}

Solution steps

\frac{d}{d x} (ln (2 - 9 x))

Apply the chain rule:

\frac{1}{2 - 9 x} \frac{d}{d x} (2 - 9 x)

= \frac{1}{2 - 9 x} \frac{d}{d x} (2 - 9 x)

\frac{d}{d x} (2 - 9 x) = - 9

= \frac{1}{2 - 9 x} (- 9)

Simplify

\frac{1}{2 - 9 x} (- 9) : - \frac{9}{2 - 9 x}

= - \frac{9}{2 - 9 x}

\frac{d}{d x} (cos (3 x^{5} + 1))

x \to \infty lim (x^{2} + y)

x y^{^{'}} + 3 y = \frac{e ^{x}}{x}

\int \frac{1}{( x ^{2} - 36 ) ^{2}} d x

\int x sin (3 x + 2) d x

What is the derivative of y=ln(2-9x) ?
The derivative of y=ln(2-9x) is -9/(2-9x)
What is the first derivative of y=ln(2-9x) ?
The first derivative of y=ln(2-9x) is -9/(2-9x)