What is the solution for y^'=(y^3-3)/((3xy^2)) ?

The solution for y^'=(y^3-3)/((3xy^2)) is y=\sqrt[3]{c_{1}x+3}

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y^'=(y^3-3)/((3xy^2))

y^{^{'}} = \frac{y ^{3} - 3}{( 3 x y ^{2} )}

Solution steps

y^{'} (x) = \frac{y ^{3} - 3}{( 3 x y ^{2} )}

Solve separable ODE:

f (x) = \frac{5 x}{e ^{x}}

\frac{1}{3 x ^{2} + 2 x}

\frac{d}{d x} (3 (x^{2} + y^{2})^{2})

\int_{0}^{1} x^{- 1} d x

y = 4 cot (3 - 2 x)

What is the solution for y^'=(y^3-3)/((3xy^2)) ?
The solution for y^'=(y^3-3)/((3xy^2)) is y=\sqrt[3]{c_{1}x+3}