What is the integral of e^{(-t^2)/2} ?

The integral of e^{(-t^2)/2} is (pi/2)^{1/2}\erf(t/(sqrt(2)))+C

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integral of e^{(-t^2)/2}

\int e^{\frac{- t ^{2}}{2}} d t

(\frac{π}{2})^{\frac{1}{2}} erf (\frac{t}{2}) + C

Solution steps

\int e^{\frac{- t ^{2}}{2}} d t

Simplify

= \int e^{- \frac{t ^{2}}{2}} d t

Apply exponent rule:

\frac{a ^{n}}{b ^{n}} = (\frac{a}{b})^{n}

\frac{t ^{2}}{2} = (\frac{t}{2})^{2}

= \int e^{- (\frac{t}{2})^{2}} d t

Apply u-substitution

: \int e^{- u^{2}} 2 d u

= \int e^{- u^{2}} 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{- u^{2}} d u

Use the nonelementary integral:

\int e^{- u^{2}} d u = \frac{π}{2} erf (u)

= 2 \frac{π}{2} erf (u)

Substitute back

u = \frac{t}{2}

= 2 \frac{π}{2} erf (\frac{t}{2})

Simplify

2 \frac{π}{2} erf (\frac{t}{2}) : (\frac{π}{2})^{\frac{1}{2}} erf (\frac{t}{2})

= (\frac{π}{2})^{\frac{1}{2}} erf (\frac{t}{2})

Add a constant to the solution

= (\frac{π}{2})^{\frac{1}{2}} erf (\frac{t}{2}) + C

x \to + (- 2) - lim (\frac{1}{x ^{2} - 4})

\frac{d}{d x} (cos (wt))

\int \frac{ln ^{2} ( x )}{x} d x

x 5^{6 x + 1}

f (x) = \frac{x ^{2} - 1}{x + 3}

What is the integral of e^{(-t^2)/2} ?
The integral of e^{(-t^2)/2} is (pi/2)^{1/2}\erf(t/(sqrt(2)))+C