What is the solution for (dy)/(dx)=(x+y-1)^2 ?

The solution for (dy)/(dx)=(x+y-1)^2 is y=tan(x+c_{1})-x+1

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(dy)/(dx)=(x+y-1)^2

\frac{d y}{d x} = (x + y - 1)^{2}

y = tan (x + c_{1}) - x + 1

Solution steps

\frac{d y}{d x} = (x + y - 1)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x + 1

y = tan (x + c_{1}) - x + 1

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What is the solution for (dy)/(dx)=(x+y-1)^2 ?
The solution for (dy)/(dx)=(x+y-1)^2 is y=tan(x+c_{1})-x+1