What is the limit as s approaches-1 of 1/(s^2+2s+1) ?

The limit as s approaches-1 of 1/(s^2+2s+1) is infinity

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limit as s approaches-1 of 1/(s^2+2s+1)

s \to - 1 lim (\frac{1}{s ^{2} + 2 s + 1})

\infty

Solution steps

s \to - 1 lim (\frac{1}{s ^{2} + 2 s + 1})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

s \to - 1 - lim (\frac{1}{s ^{2} + 2 s + 1}) = \infty

s \to - 1 + lim (\frac{1}{s ^{2} + 2 s + 1}) = \infty

= \infty

6 - 5 x

(\frac{( x + 11 )}{( x - 11 )})^{5}

\frac{d}{d x} (3 x - x^{2},)

y = x - 1

(2 x + 1)^{2}

What is the limit as s approaches-1 of 1/(s^2+2s+1) ?
The limit as s approaches-1 of 1/(s^2+2s+1) is infinity