What is (\partial)/(\partial c)(16dc^2) ?

The answer to (\partial)/(\partial c)(16dc^2) is 32dc

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(\partial)/(\partial c)(16dc^2)

\frac{\partial}{\partial c} (16 d c^{2})

32 d c

Solution steps

\frac{\partial}{\partial c} (16 d c^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 d \frac{\partial}{\partial c} (c^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 d \cdot 2 c^{2 - 1}

Simplify

= 32 d c

\frac{d y}{d x} + \frac{y}{x} = 3 x^{3} y^{2}

\int 3 sec^{2} (x) + 2 d x

\frac{\partial}{\partial y} (x y e^{7 y})

3 x^{2} y^{2} d x + (2 x^{3} y + 4 y^{3}) d y = 0

\frac{d y}{d x} + (\frac{5}{x}) y = - 2 x - 2

What is (\partial)/(\partial c)(16dc^2) ?
The answer to (\partial)/(\partial c)(16dc^2) is 32dc