What is the solution for 3x^2y^2dx+(2x^3y+4y^3)dy=0 ?

The solution for 3x^2y^2dx+(2x^3y+4y^3)dy=0 is

Popular >

3x^2y^2dx+(2x^3y+4y^3)dy=0

3 x^{2} y^{2} d x + (2 x^{3} y + 4 y^{3}) d y = 0

y = \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = \frac{- x ^{3} - x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} - x ^{6} + c _{1}}{2}

Solution steps

3 x^{2} y^{2} d x + (2 x^{3} y + 4 y^{3}) d y = 0

Solve exact ODE:

y = \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = \frac{- x ^{3} - x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} - x ^{6} + c _{1}}{2}

y = \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = \frac{- x ^{3} - x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} - x ^{6} + c _{1}}{2}

\frac{d y}{d x} + (\frac{5}{x}) y = - 2 x - 2

\int_{0}^{1} 10 cos (x^{2}) d x

\int (x + 3) (x - 5) d x

\int_{2}^{6} \frac{1}{3 x - 2} d x

\frac{d}{d t} (2 cos (t) + 2 sin (t))

What is the solution for 3x^2y^2dx+(2x^3y+4y^3)dy=0 ?
The solution for 3x^2y^2dx+(2x^3y+4y^3)dy=0 is