What is the integral of i/x ?

The integral of i/x is iln|x|+C

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integral of i/x

\int \frac{i}{x} d x

i ln ∣ x ∣ + C

Solution steps

\int \frac{i}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= i \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= i ln ∣ x ∣

Add a constant to the solution

= i ln ∣ x ∣ + C

\frac{d}{d x} (ln (x^{2} - 10 x))

\frac{\partial}{\partial x} (e^{- \frac{x}{a}})

\frac{\partial}{\partial y} (2 x + 3 y - 4)

\frac{\partial}{\partial y} (e^{x} y^{3} + 2 y e^{2 x})

\frac{d y}{d x} = - \frac{y}{10}