What is the derivative of sin(2x+cos(3x)) ?

The derivative of sin(2x+cos(3x)) is cos(2x)*2-sin(3x)*3

What is the first derivative of sin(2x+cos(3x)) ?

The first derivative of sin(2x+cos(3x)) is cos(2x)*2-sin(3x)*3

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\frac{d}{d x} (sin (2 x) + cos (3 x))

cos (2 x) \cdot 2 - sin (3 x) \cdot 3

Solution steps

\frac{d}{d x} (sin (2 x) + cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (2 x)) + \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= cos (2 x) \cdot 2 - sin (3 x) \cdot 3

f (x) = π^{3 x + 3}, at x = 2

121 y^{^{''}} + 88 y^{^{'}} + 12 y = 0

4 + cot^{2} (x)

x + 5

\int_{0}^{N} e^{- s t} e^{5 t} d t

What is the derivative of sin(2x+cos(3x)) ?
The derivative of sin(2x+cos(3x)) is cos(2x)*2-sin(3x)*3
What is the first derivative of sin(2x+cos(3x)) ?
The first derivative of sin(2x+cos(3x)) is cos(2x)*2-sin(3x)*3