What is the derivative of ln(3x^2-y^3-3) ?

The derivative of ln(3x^2-y^3-3) is (6x-3y^2\frac{dy)/(dx)}{3x^2-y^3-3}

What is the first derivative of ln(3x^2-y^3-3) ?

The first derivative of ln(3x^2-y^3-3) is (6x-3y^2\frac{dy)/(dx)}{3x^2-y^3-3}

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Popular >

\frac{d}{d x} (ln (3 x^{2} - y^{3} - 3))

\frac{6 x - 3 y ^{2} \frac{d y}{d x}}{3 x ^{2} - y ^{3} - 3}

Solution steps

\frac{d}{d x} (ln (3 x^{2} - y^{3} - 3))

Apply the chain rule:

\frac{1}{3 x ^{2} - y ^{3} - 3} \frac{d}{d x} (3 x^{2} - y^{3} - 3)

= \frac{1}{3 x ^{2} - y ^{3} - 3} \frac{d}{d x} (3 x^{2} - y^{3} - 3)

\frac{d}{d x} (3 x^{2} - y^{3} - 3) = 6 x - 3 y^{2} \frac{d y}{d x}

= \frac{1}{3 x ^{2} - y ^{3} - 3} (6 x - 3 y^{2} \frac{d y}{d x})

Simplify

\frac{1}{3 x ^{2} - y ^{3} - 3} (6 x - 3 y^{2} \frac{d y}{d x}) : \frac{6 x - 3 y ^{2} \frac{d y}{d x}}{3 x ^{2} - y ^{3} - 3}

= \frac{6 x - 3 y ^{2} \frac{d y}{d x}}{3 x ^{2} - y ^{3} - 3}

\frac{d}{d x} (3^{x^{2} c o t (2 x)})

\frac{d}{d x} (\frac{8}{3 x})

\frac{x + 3}{x - 3}

\int 7 e^{10 x} d x

\int 4 cos (θ) d θ

What is the derivative of ln(3x^2-y^3-3) ?
The derivative of ln(3x^2-y^3-3) is (6x-3y^2\frac{dy)/(dx)}{3x^2-y^3-3}
What is the first derivative of ln(3x^2-y^3-3) ?
The first derivative of ln(3x^2-y^3-3) is (6x-3y^2\frac{dy)/(dx)}{3x^2-y^3-3}