What is the integral of 4cos(θ) ?

The integral of 4cos(θ) is 4sin(θ)+C

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integral of 4cos(θ)

\int 4 cos (θ) d θ

4 sin (θ) + C

Solution steps

\int 4 cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= 4 sin (θ)

Add a constant to the solution

= 4 sin (θ) + C

\int (3 x + 1) 3 3 x^{2} + 2 x d x

\int \frac{x ^{3} + x ^{2} + x - 2}{x ^{3} - x ^{2}} d x

4 - x^{2}, \frac{1}{4} x^{3} - 2, 1, 2

\frac{d y}{d x} = \frac{8 x ^{2}}{9 + x ^{3}}

h^{2} + 7 h + 40