What is the derivative of 640(1.06)^t ?

The derivative of 640(1.06)^t is 37.29210…*1.06^t

What is the first derivative of 640(1.06)^t ?

The first derivative of 640(1.06)^t is 37.29210…*1.06^t

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derivative of

640 (1.06)^{t}

37.29210 \dots \cdot 1.0 6^{t}

Solution steps

\frac{d}{d t} (640 \cdot 1.0 6^{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 640 \frac{d}{d t} (1.0 6^{t})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 640 \cdot 1.0 6^{t} ln (1.06)

Simplify

640 \cdot 1.0 6^{t} ln (1.06) : 37.29210 \dots \cdot 1.0 6^{t}

= 37.29210 \dots \cdot 1.0 6^{t}

f (x) = 2 x^{2} - 32

f (t) = 5 + 4 \cdot δ (t)

\frac{d}{d x} (ln (1 + sin (x)))

\frac{d}{d x} ((f (x) (6 x))^{2} - 2)

x \to 0 + lim (2 + ln (x))

What is the derivative of 640(1.06)^t ?
The derivative of 640(1.06)^t is 37.29210…*1.06^t
What is the first derivative of 640(1.06)^t ?
The first derivative of 640(1.06)^t is 37.29210…*1.06^t