What is area f(x)=x^5+4,g(x)=x+4 ?

The answer to area f(x)=x^5+4,g(x)=x+4 is 2/3

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area f(x)=x^5+4,g(x)=x+4

area

f (x) = x^{5} + 4, g (x) = x + 4

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} x^{5} + 4 - (x + 4) d x

Solve

\int_{- 1}^{1} x^{5} + 4 - (x + 4) d x : \frac{2}{3}

The area is:

= \frac{2}{3}

f (x) = - \frac{1}{2 1 - x}, at x = - 8

\int \frac{1}{u 7 - u ^{2}} d u

f^{^{'}} (x) = \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}}

\frac{d}{d x} (ln (1 + e^{2 x}))

x \to - 1 lim (\frac{x ^{2} - x}{x})

What is area f(x)=x^5+4,g(x)=x+4 ?
The answer to area f(x)=x^5+4,g(x)=x+4 is 2/3