What is (\partial)/(\partial y)(x^2-xy) ?

The answer to (\partial)/(\partial y)(x^2-xy) is -x

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(\partial)/(\partial y)(x^2-xy)

\frac{\partial}{\partial y} (x^{2} - x y)

- x

Solution steps

\frac{\partial}{\partial y} (x^{2} - x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x y) = x

= 0 - x

Simplify

= - x

\int_{0}^{l n (5)} x e^{x} d x

e^{t} cos (2 t)

\frac{d}{d x} (e^{0 x})

f (x) = \frac{π x}{2}

\frac{d}{d x} (64 x - \frac{x ^{3}}{3})

What is (\partial)/(\partial y)(x^2-xy) ?
The answer to (\partial)/(\partial y)(x^2-xy) is -x