What is the derivative of y=e^{4x^2+1} ?

The derivative of y=e^{4x^2+1} is e^{4x^2+1}*8x

What is the first derivative of y=e^{4x^2+1} ?

The first derivative of y=e^{4x^2+1} is e^{4x^2+1}*8x

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derivative of

y = e^{4 x^{2} + 1}

e^{4 x^{2} + 1} \cdot 8 x

Solution steps

\frac{d}{d x} (e^{4 x^{2} + 1})

Apply the chain rule:

e^{4 x^{2} + 1} \frac{d}{d x} (4 x^{2} + 1)

= e^{4 x^{2} + 1} \frac{d}{d x} (4 x^{2} + 1)

\frac{d}{d x} (4 x^{2} + 1) = 8 x

= e^{4 x^{2} + 1} \cdot 8 x

\frac{5 t}{1 + 2 t ^{2}}

f (x) = 7 x + 1, (9, 8)

\int \frac{a}{a ^{2} + x ^{2}} d x

\int \frac{1}{5 x + 4} d x

n = 1 \sum \infty \frac{8 n}{7 - 4 n}

What is the derivative of y=e^{4x^2+1} ?
The derivative of y=e^{4x^2+1} is e^{4x^2+1}*8x
What is the first derivative of y=e^{4x^2+1} ?
The first derivative of y=e^{4x^2+1} is e^{4x^2+1}*8x