What is the derivative of 1+12sqrt(t) ?

The derivative of 1+12sqrt(t) is 6/(sqrt(t))

What is the first derivative of 1+12sqrt(t) ?

The first derivative of 1+12sqrt(t) is 6/(sqrt(t))

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derivative of

1 + 12 t

\frac{6}{t}

Solution steps

\frac{d}{d t} (1 + 12 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (12 t)

\frac{d}{d t} (1) = 0

\frac{d}{d t} (12 t) = \frac{6}{t}

= 0 + \frac{6}{t}

Simplify

= \frac{6}{t}

y^{^{''}} + 9 y = sin (3 t)

\frac{d}{d x} (8 8 x^{7} - 10)

\frac{d y}{d x} = arctan (- 6 x)

y = (\frac{2 x + 1}{3 x - 1})^{4}

\int e^{- 6 x} d x

What is the derivative of 1+12sqrt(t) ?
The derivative of 1+12sqrt(t) is 6/(sqrt(t))
What is the first derivative of 1+12sqrt(t) ?
The first derivative of 1+12sqrt(t) is 6/(sqrt(t))