What is (\partial)/(\partial x)(4sin(x)cos(y)) ?

The answer to (\partial)/(\partial x)(4sin(x)cos(y)) is 4cos(y)cos(x)

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(\partial)/(\partial x)(4sin(x)cos(y))

\frac{\partial}{\partial x} (4 sin (x) cos (y))

4 cos (y) cos (x)

Solution steps

\frac{\partial}{\partial x} (4 sin (x) cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 cos (y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 4 cos (y) cos (x)

\frac{\partial}{\partial K} (L^{\frac{1}{2}} K^{\frac{1}{2}})

x \to 4 lim (x + 4)

f (x) = 4 x - 7

\int_{0}^{4} y d y

\frac{d}{d x} ((2 x + 5)^{4})

What is (\partial)/(\partial x)(4sin(x)cos(y)) ?
The answer to (\partial)/(\partial x)(4sin(x)cos(y)) is 4cos(y)cos(x)