What is the normal of y=6xe^x,(0,0) ?

The normal of y=6xe^x,(0,0) is y=-1/6 x

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normal of y=6xe^x,(0,0)

normal of

y = 6 x e^{x}, (0, 0)

y = - \frac{1}{6} x

Solution steps

Find the slope of

y = 6 x e^{x} : \frac{d y}{d x} = 6 (e^{x} + e^{x} x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{6}

Find the line with slope m=

- \frac{1}{6}

and passing through

(0, 0) : y = - \frac{1}{6} x

y = - \frac{1}{6} x

\int 14 x 7 x - 3 d x

\frac{d}{d x} (e^{5 x s i n (2 x)})

\int 5 cos (x) + 3 sin (x) d x

f (x) = 2 x^{2} + 8 x

n = 1 \sum \infty 2 (- \frac{1}{2})^{n}